Title: نهائي / إختيار من متعدد / سهل
Course: مختبر فيزياء عامه 2 الشعبة 10 عملي

Q: In the experiment of equipotential surface and electric field lines, the Figure shows two points of charge. which one is correct:

[Image]
- a
- b
- c
- d
A: a

Q: In the experiment of equipotential surface and electric field lines, the Figure shows two lines of charges. which one is correct:

[Image]
- a
- b
- c
- d
A: a

Q: In the experiment of equipotential surface and electric field lines, the Figure shows one line and point of charge. which one is correct:

[Image]
- a
- b
- c
A: a

Q: 1-    What is the maximum value in the tolerance range of a resistor with color code red-violet-orange-gold?
- 28.35 kΩ
- 27 kΩ
- 29.7 kΩ
- 32.4 kΩ
A: 28.35 kΩ

Q: What is the minimum  value in the tolerance range of a resistor with color code red-violet-orange-gold?
- 25.65 kΩ
- 27 kΩ
- 29.7 kΩ
- 32.4 kΩ
A: 25.65 kΩ

Q: What is the color code for a 4.7 kΩ resistor with 5% tolerance?
- yellow-violet-red-gold
- green-violet-red-gold
- yellow-violet-orange-gold
- yellow-blue-red-gold
A: yellow-violet-red-gold

Q: A solenoid 15.0 cm long has 600 turns and carries a current of 5.0 A. if 2.0 cm segment of a current balance arm is balanced inside the solenoid when the magnetic force on the segment 1x10^-5 N. the current in it is
- 20 mA
- 2 mA
- 1.5 mA
- 0.07 A
- None
A: 20 mA

Q: The magnetic field strength inside a certain solenoid is 50 mT. If a 4 cm conducting strip, which is perpendicular to the magnetic field inside the solenoid, the current in the conducting strip is 2 A. The magnetic force is
- 4 x 10 ^-3 N
- 2 x 10 ^-3 N
- 0.5 x 10 ^-3 N
- 3 x 10 ^-3 N
- None
A: 4 x 10 ^-3 N

Q: Kh-10M. A student measures the angle of the compass of the tangent galvanometer respect to the earth magnetic field B_e (S-N), when the plane of the coil of the galvanometer is parallel to the earth’s magnetic field, and obtain an angle = 45^o^ and current I= 20 mA.

What is the number of turns of the circular coils of the tangent galvanometer of diameter 15 cm, if the horizontal earth’s magnetic field is 40 micro Tesla?
- 400
- 239
- 398
- 120
A: 239

Q: Kh-12E. in the Fig. shown the compass of the tangent galvanometer makes angle θ with respect to the earth magnetic field B_e (S-N), when the plane of the coil is parallel to the earth’s magnetic field.

The magnetic field produced by the coil is pointing  in the direction of:

[Image]
- East
- West
- North
- South
A: West

Q: Kh-13E. If the compass of the tangent galvanometer makes angle θ with respect to the earth magnetic field B_e (S-N), when the plane of the coil is parallel to the earth’s magnetic field is as shown in Fig.

What is the direction of the current in the coil?

[Image]
- Clockwise
- Counterclockwise
- In the direction of the magnetic field of coil.
- Cannot be determined
A: Clockwise

Q: Two equipotential surfaces with V = 2 volts and V=4 volts are drawn between two point charges, as shown in fig.1. Electric field lines will be directed .........

[Image]
- From right to left
- from left to right
- parallel to the x-axis
- from south to north
A: From right to left

Q: Two equipotential surfaces with V = 2 volts and V=4 volts are drawn between two point charges, as shown in fig.1. The change in the potential energy as a charge of 1C moved from 1 to 2 to 3 is .....

[Image]
- 4J
- 0 J
- 2 J
- 10 J
A: 2 J

Q: The “Time/Div” setting of an oscilloscope that displays the signal in Fig. has value of 25 ms.

The frequency of the signal is ........

[Image]
- 10 Hz
- 40 Hz
- 0.1 Hz
- 100 Hz
A: 10 Hz

Q: Kh-17E. For the tangent galvanometer, when tanα , α is the angle of the compass with respect to the earth magnetic field Be (S-N). The magnitude of the horizontal magnetic field of the earth Be is related to the magnetic field of the coil B_L by
- B_e = B_L/tanα
- B_e = B_L.tanα
- B_e = B_L.cosα
- B_e = B_L/sinα
A: B_e = B_L/tanα

Q: Kh-18E. A student measures the angle of the compass of the tangent galvanometer respect to the earth magnetic field B_e (S-N), when plane of the coil is parallel to the earth’s magnetic field and uses alternating current (AC current) to flow through the coil. The student:
- will succeed to determine B_e
- will not be able to determine B_e
- will determine B_e correctly
- will change current and obtain the corresponding angle
A: will not be able to determine B_e

Q: For the circuit of Fig. 3a the data taken by the

voltmeter V and the ammeter A is plotted in Fig. 3b,

[Image]the equivalent resistance R_eq in ohms of the two resistor is combination is
- 6
- 2
- 3
- 0.2
A: 2

Q: Kh-1M. For the Fig. shown the of the angle of the compass is 45^o with respect to the earth magnetic field Be (S-N). The plane of the coil of the galvanometer is parallel B_e.

[Image]What is the magnitude of the horizontal magnetic field  of the earth Be (in micro Tesla) if the current in the coil I = 7.5 mA.  (The number of turns of the coil is N=500, the diameter is 15 cm)
- 31.4
- 55.8
- 62.8
- 25.5
A: 31.4

Q: For circuit of Fig. 3a the data taken by the  voltmeter V and the ammeter A is plotted in Fig. 3b

[Image]the value of R in ohms is
- 6
- 2
- 5/6
- 1/2
A: 6

Q: The potentiometer wire AB = 100 cm is connected to = 6 V. The length at the balance point (I_G=0), AC = L_AC = L_x = 40 cm for the unknown battery E_x. [Image]

Find E_x (in volts) .
- 2.8 V
- 3 V
- 1.5
- 2.4
A: 2.4

Q: Kh-8H. A student measures the angle of the compass of the tangent galvanometer respect to the earth magnetic field B_e (S-N), when the plane of the coil of the galvanometer is parallel to the earth’s magnetic field, and obtain an angle α= 38^o^ and current I= 10 mA.

What is the current in mA when the angle α is 50^o?
- 15.3
- 20
- 12.5
- 20.1
A: 15.3

Q: The resistance of a coil at different temperatures is plotted in Fig. 5.

The resistance R_T at temperature T= 0C and the zero kelvin temperature are

[Image](i.e. R_T at T=0  and   the 0K are)
- 30 Ohm, - 300 ^oC
- 30 Ohm, 300 ^oC
- 300 Ohm, 30 ^oC
- 300 Ohm, - 30 ^oC
A: 30 Ohm, - 300 ^oC

Q: When V_AC vs the current i in the resistor R is plotted as shown in fig.

Find E_x and r the internal resistance of  E_x from the graph.

[Image]E_X and r   are  .............
- 5 V, 2 ohm
- 2 V, 5 ohm
- 1V , 0.1 ohm
- 2.3V, 4 ohm
A: 2 V, 5 ohm

Q: [Image]

Kh-2H. The compass of the tangent galvanometer was at angle of  θ=45^o with respect to the earth magnetic field B_e (S-N),  the plane of the coil  is parallel to B_e as shown in Fig_.

What is the magnitude of the horizontal magnetic field of the earth B_e  (in micro Tesla) if the current in the coil I = 15 mA. (The number of turns of the coil is N=500, the diameter is 15 cm)
- 29.3
- 60.0
- 62.8
- 15.2
A: 62.8

Q: Kh-3H. For the tangent galvanometer, when tanα, α is the angle of the compass with respect to the earth magnetic field Be (S-N), versus the current in the coil I in mA is plotted as shown in the figure.

What is the magnitude of the horizontal magnetic field of the earth Be (in micro Tesla). (The number of turns of the coil is N=500, the diameter is 15 cm)

[Image]
- 33
- 66
- 15
- 53
A: 33

Q: Kh-4H. For the tangent galvanometer, when tanα , α is the angle of the compass with respect to the earth magnetic field Be (S-N), versus the current in the coil I in mA is plotted as shown in the figure.

What is the magnitude of the horizontal magnetic field of the earth Be (in micro Tesla). (The number of turns of the coil is N=500, the diameter is 15 cm)

[Image]
- 42
- 21
- 84
- 77
A: 42

Q: Kh-5M. For the tangent galvanometer, when tanα, α is the angle of the compass with respect to the earth magnetic field Be (S-N), versus the current in the coil I in mA is plotted as shown in the figure. What is the magnitude of the horizontal magnetic field of the earth Be (in micro Tesla). (The number of turns of the coil is N=50 [Image]0, the diameter is 15 cm)
- 42
- 21
- 84
- 77
A: 84

Q: Kh-5M. For the tangent galvanometer α is the angle of the compass with respect to the earth magnetic field Be (S-N), when the current in the coil I in mA versus tanα is plotted to get the slope S, then the horizontal magnetic field of the earth Be is proportional to
- S
- 2S
- 1/S
- S^2
A: S / 1/S

Q: Kh-6M. For the tangent galvanometer,  α is the angle of the compass with respect to the earth magnetic field Be (S-N).

when tanα ,versus the current in the coil I in mA is plotted as shown in the figure.

What is the magnitude of the horizontal magnetic field of the earth Be (in micro Tesla). (The number of turns of the coil is N=500, the diameter is [Image] 15 cm)
- 42
- 21
- 84
- 63
A: 63

Q: Kh-7M. The compass of the tangent galvanometer align itself at an angle of α with respect to the earth magnetic field B_e (S-N), when the plane of the coil of the galvanometer is parallel to the earth’s magnetic field as shown in Fig_.

What is the magnitude of the horizontal magnetic field of the earth B_e (in micro Tesla) if the magnetic field of the coil is B_L = 30 µT and α= 37^o.

[Image]
- 25
- 40
- 23
- 60
A: 40

Q: Kh-8H. A student measures the angle of the compass of the tangent galvanometer respect to the earth magnetic field B_e (S-N), when the plane of the coil of the galvanometer is parallel to the earth’s magnetic field, and obtain an angle = 38^o^ and current I= 6 mA.

What is the current in mA when the angle is 50^o?
- 9.15
- 3.93
- 12.51
- 20.1
A: 9.15

Q: Kh-9M. A student measures the angle of the compass of the tangent galvanometer respect to the earth magnetic field B_e (S-N), when the plane of the coil of the galvanometer is parallel to the earth’s magnetic field.  If the  angle = 45^o^ and current I= 10 mA.

The diameter of the coil is 10cm. when B_e = 60 micro Tesla,

what is the number of turns N?
- 477
- 500
- 398
- 250
A: 477

Q: Kh.11-1M. A student measures the horizontal component of the magnetic field of earth using he tangent galvanometer.

The value of B_e may be obtained according to your results of the experiment is?
- 0.025 mT
- 25 mT
- 50 mA
- 0.025 μT
A: 0.025 mT

Q: In the RC circuit, when a resistor R=100 M\( \Omega \) is connected to a capacitor C= 1µF (initially uncharged) and a battery, then the capacitor will reach 0.63 of its maximum charge in
- 100 sec
- 1 sec
- 5 sec
- Instantly (less than 1 ms)
A: 100 sec

Q: 1)    In the RC circuit, when a resistor R=100 M\( \Omega \) is connected to a fully charged capacitor C= 1µF , then the capacitor will lose 63% of its maximum charge in
- 100 sec
- 1 sec
- 5 sec
- 10 sec
A: 100 sec

Q: The side figure represents the voltage across a capacitor that is

[Image]
- Charging
- Discharging
- Neither charging nor discharging
- Can't tell whether it is charging or discharging
A: Charging

Q: The potentiometer wire AB = 100 cm is connected to E = 6 V. The length at the balance point

  (I_G=0) AC = L_x = 50 cm for the unknown battery E_x, then:

[Image]
- 3
- 2
- 1.5
- 1
A: 3

Q: The electromotive force of a cell is its terminal voltage when
- Its resistance is maximum
- Its resistance is zero
- Maximum current flow through it
- no current flow through it
A: Its resistance is zero

Q: Referring to the right figure (AC bridge which used to calculate the unknown capacitor) answer the following question.:If Lx= 40 cm and Cs= 400 μF, then Cx equal to 600 μF

If another capacitor C_x=600 µF is joint in parallel to Cx WHAT WOULD BE Lx

[Image]
- 25cm
- 20cm
- 40cm
- 80cm
A: 25cm

Q: Junction rule  depends on conservation of  :
- momentum
- charge
- Energy
- mass
A: charge

Q: Loop Rule depends on conservation of  :
- momentum
- charge
- Energy
- mass
A: Energy

Q: In fig. is, at the balance condition

 [Image]

Write the equation for the balance condition to find Cx.
- Cx/C=R2/R1
- Cx/C=R1/R2
- Cx .C=R1.R2
- C.R1=Cx.R2
A: Cx/C=R2/R1

Q: The  figure7  is at the balance condition and if

R₁ = 100 \( \Omega \)  , R₂= 2000 \( \Omega \),

C = 100 μF.

Find   Cx in μF

[Image]
- 5
- 2000
- 100
- 20
A: 2000

Q: - Relation between currents according to Kirchhoff's current low is:

[Image]
- I₁=I_2= I_3=1_4=I_5
- I₁+I_4+I_3= I_5+I_2
- I₁+I_4=I_2+I_3+I_5
- 1₁-1_5=1_2-1_3-1_4
A: I₁+I_4=I_2+I_3+I_5

Q: In Ammeter Bridge, the null point is found at a distance of 75 cm from B. determine the value of  Cx? in μF    (LAB = 100 cm)

[Image]
- 111
- 100
- 300
- 333
A: 300

Q: - A metre bridge is set-up as shown, to determine an unknown resistance R using a standard 550 resistor. The galvanometer shows null point when tapping-key is at 20 cm

The determined value of R is:

[Image]
- 0.072Ω
- 29 Ω 2
- 220Ω
- 13.7 Ω
A: 220Ω
Feedback: a- b- c- d-

Q: - In potentiometer experiment, balance point is obtained at a particular point for a cell on potentiometer wire x cm long. If the length of the potentiometer wire is decreased without changing the cell, the balancing length will :
- Increase
- decrease
- not change
- zero
A: Increase

Q: - In a potentiometer experiment, the balancing length with a cell is 240 cm. On shunting the cell with a resistance of 2 Ω  , the balancing length becomes 120 cm. The internal resistance of the cell is
- 4
- 1
- 0.5
- 2
A: 2